a stone is dropped from a point 0.4m above the top of a 0.5m high window.find the time taken by the stone to pass the span of the window.
Answers
Given:
Point above the top = 0.4m
Height of Window = 0.5m
To Find:
Time taken by stone to pass span of window
Solution:
Total height = 0.4 + 0.5
= 0.9m
Time taken to cover 0.9m = √2h/g = √2(0.9)/10 = 3/10√2
Time taken to cover 0.4m = √2h/g = √2(0.4)/10 = 2/10√2
Total time taken = 3/10√2 - 2/10√2
= √2/10
Answer: The time taken by stone to pass the window span is √2/10 seconds
Time taken to pass the window = 0.14 seconds.
Explanation:
Height of window = 0.5m
Height of the stone = 0.4m above window
Total distance traveled by stone = 0.5 + 0.4 = 0.9 m
We know that distance = 1/2 gt²
So t² = 2/g(distance)
Therefore t = √(2s/g)
Time taken by the stone to cover full distance = √(2/g) * s where g is taken as 10 m/s2
= √2(0.9)/10
= √2(9)/100
= 3/10*√2
Time taken to cover 0.4 = = √2(0.4)/10 = 2/10 *√2
Time taken to pass the window = 3/10√2 - 2/10√2 = 1/10(√2) = 1.414/10 = 0.14 seconds.