Question

A stone is dropped from a point 2 metre above the top of a window of hight 2m what time does the stone take to pass against the window​

Answer 1

Explanation:

We can use the equation Yf-Y0=V0*t + 1/2*a*t^2. since it falls 2 meters, starts with initial velocity 0m/s (since it was dropped), and is in freefall, we know that Yf-Y0=-2m, V0 = 0, and a= -9.8 m/s^2. Plugging into our equation, we obtain: -2 = 0*t -9.8*t^2, and this t = sqrt(2/9.8) which is about .45 seconds.