Question

A stone is dropped from a point 2 metre above the top of a window of hight 2m what time does the stone take to pass against the window​

Answer 1

Answer:

We can use the equation Yf-Y0=V0*t + 1/2*a*t^2. since it falls 2 meters, starts with initial velocity 0m/s (since it was dropped), and is in freefall, we know that Yf-Y0=-2m, V0 = 0, and a= -9.8 m/s^2. Plugging into our equation, we obtain: -2 = 0*t -9.8*t^2, and this t = sqrt(2/9.8) which is about .45 seconds.

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Answer 2

We want to calculate the time it takes for the stone to fall 4 metres. A stone is dropped from a point 2 m above the top of a window of the height of 2 m.