Question

A stone is dropped from a point at 3 : 30 : 32 p.m (hour : minute : second). Another stone is dropped from the same point at 3 : 30 : 34 p.m. Find the separation between the stones at 3 : 30 : 35 p.m.​

Answer 1

Given:

A stone is dropped from a point at 3 : 30 : 32 p.m (hour : minute : second). Another stone is dropped from the same point at 3 : 30 : 34 p.m.

To find:

Separation between stones at 3:30:35 pm.

Calculation:

For the 1st stone , the time for which it falls is :

3:30:35pm - 3:30:32pm = 3 seconds.

For the 2nd stone , the time for which it falls is :

3:30:35pm - 3:30:34pm = 1 second.

So, distance travelled by 1st stone:

$\therefore \: d1 = \dfrac{1}{2} g {(t1)}^{2}$

$\implies \: d1 = \dfrac{1}{2} \times 10 \times {3}^{2}$

$\implies \: d1 = 45 \: m$

So, distance travelled by 2nd stone:

$\therefore \: d2 = \dfrac{1}{2} g {(t2)}^{2}$

$\implies \: d2 = \dfrac{1}{2} \times 10 \times {1}^{2}$

$\implies \: d2 = 5 \: m$

So, separation between them:

$\therefore \: \Delta d = d1 - d2$

$\implies \: \Delta d = 45 - 5$

$\implies \: \Delta d = 40 \: m$

So, separation is 40 metres.

Answer 2

see the answer above it will give you all of the things you want