a stone is dropped from a tower 45 metre high calculate its speed on reaching the earth
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Given:-
•Height of the tower(h)=45m
•Initial velocity(u)=0
•Acceleration due to gravity(g)=9.8m/s²
To find:-
•Final velocity of the stone(v)
Solution:-
By using the third equation of motion when u=0,we get----
=>v²=2gh
=>v²=2×9.8×45
=>v²=882
=>v=29.7m/s
Thus,spped of the stone on reaching the earth is 29.7m/s.
Note:-If we take g=10m/s²,then the final velocity will be 30m/s.
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