A stone is dropped from a tower it strikes
the ground after 4 sec then height of the
tower
(a) 78.4m
(b) 7.84m
(c) 784 m
(d) None of them
Answers
Answered by
4
Answer:
use this ,s=ut +1/2at^2
Explanation:
u=0 g =9.8
s=o×4+1/2×9.8×4×4
s=1/2×9.8×16
s=9.8×8
s=78.4
Answered by
13
Correct Question:-
A stone is dropped from a tower which strikes the ground after 4 seconds,then height of the tower is?
Given:-
•Time taken(t)=4s
To find:-
•Height of the tower(h)
Solution:-
We know that:-
•In this case,the initial velocity(u) of the stone will be zero as the stone was initially at rest.
•Acceleration due to gravity(g) = 9.8m/s²
Now,by using the 2nd equation of motion we get:-
=>h=ut+1/2gt²
=>h=0×4+1/2×9.8×(4)²
=>h=1/2×9.8×16
=>h=4.9×16
=>h=78.4m
Thus,height of the tower is 78.4m.
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