Question

A stone is dropped from a tower. What is the speed after it has fallen 62.5 m?​

Answer 1

Answer:

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Explanation:

Here ,

u = Initial velocity = 0

v = Final velocity

s = Distance travelled = 20m

a = acceleration = g = 10ms

−2

Now , we know that from the equation of motion that ,

v

2

=u

2

+2as

v=

u

2

+2as

v=

0+2×10×20

v=

400

ms

−1

v=20ms

−1

Answer 2

Answer:

Here ,  

u  = Initial velocity = 0

v = Final velocity  

s = Distance travelled  = 20m  

a = acceleration = g = 10ms  −2

 

Now , we know that from the equation of motion that ,

 v  2  =u  2  +2as

 v=  u  2  +2as

​  v=  0+2×10×20

​  v=  √400  ms  −1

 v=20ms  −1

 

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