Question

A stone is dropped from a tower with 0 initial velocity.It is observed that it strikes the ground after 5s . Find the velocity of impact and the height of the tower.
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Answer 1

Explanation:

initial velocity=0

time=5

gravity=10

height=?

final velocity=?

for height

we use,

s=ut+1/2at^2

S= 0+1/2*10*(5)^2

S=125

for final velocity we use

2as=v^2-u^2

2*10*125=v^2

v^2=50

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