a stone is dropped from a well from rest, the well is 50m deep. How long will it take to reach bottom of the well, given accelaration=9.8m/sec^2
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s = ut + 1/2at^2
50 = 1/2 × 98/10 × t^2
50 = 4.9 × t^2
√50/4.9 = t
t = 1.4 second
50 = 1/2 × 98/10 × t^2
50 = 4.9 × t^2
√50/4.9 = t
t = 1.4 second
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