Question

a stone is dropped from a window reaches the ground in 0.5 seconds calculate the height of the window from the ground

Answer 1

here,
u=initial speed = 0.
t = time = 0.5 sec.
a= acceleration = g = 9.8 m/sec^2

findout distance:-

s=ut+$\frac{1}{2} at^{2}$

s=0*t +$\frac{1}{2}*9.8* \frac{1}{2}* \frac{1}{2}= \frac{9.8}{8}=1.225m$

Answer 2

 using equation s = ut + 
s = distance
u=initial speed = 0.
t = time = 0.5 sec.
a= acceleration = g = 9.8 m/s²
⇒ s = 0 × 0.5 + 1/2 × 9.8 × 0.5  ×0.5
⇒ s = 1.2 mtrs.