Physics, asked by shreyasikumari133, 7 months ago

A stone is dropped from an a heighted of 45 m. If the stone falls with anacceleration of 10 m/s2 with what velocit will it strike the ground? after what
time will it strike the ground?​

Answers

Answered by Anonymous
2

When the stone is dropped, initial velocity = 0.

Now, h=(1/2)gt

2

Distance travelled in t

n

sec can be written as h

n

=(1/2)gt

n

2

Distance travelled in t

n

−1 sec can be written as h

n−1

=(1/2)g(t

n

−1)

2

So, h

n

−h

n−1

= journey in nth second = (1/2)g(t

n

2

−(t

n

−1)

2

)

=(1/2)g(2t

n

−1)=g(t

n

−1/2)

Now using h=(1/2)gt

2

for h = 45m we get t = 3 sec

So, in the 3rd second the stone will travel 10 X 2.5 m = 25 m.

Answered by Anonymous
2

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