A stone is dropped from an a heighted of 45 m. If the stone falls with anacceleration of 10 m/s2 with what velocit will it strike the ground? after what
time will it strike the ground?
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Answered by
2
When the stone is dropped, initial velocity = 0.
Now, h=(1/2)gt
2
Distance travelled in t
n
sec can be written as h
n
=(1/2)gt
n
2
Distance travelled in t
n
−1 sec can be written as h
n−1
=(1/2)g(t
n
−1)
2
So, h
n
−h
n−1
= journey in nth second = (1/2)g(t
n
2
−(t
n
−1)
2
)
=(1/2)g(2t
n
−1)=g(t
n
−1/2)
Now using h=(1/2)gt
2
for h = 45m we get t = 3 sec
So, in the 3rd second the stone will travel 10 X 2.5 m = 25 m.
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