A stone is dropped from cliff into a lake 80 m deep. Another cliff which is 200 m away from the lake reflects the sound of splash . What is the time difference between the sounds of the first splash and echo of splash? Take speed of sound is 340 ms1 and g = 10 msal 3N
Answers
Answered by
3
Answer:
Correct option is
C
11.5 s
Height of the tower S=500 m
Initial speed of the stone u=0
Acceleration due to gravity acting on the stone g=10m/s2
Using S=ut1+21gt12
where t1 is the time taken by the stone to reach the lake.
∴ 500=0+21(10)t12
We get t1=10 s
Speed of sound in air v=330m/s
Time taken by the sound of splash to reach the top of tower t2=vS
∴ t2=330500=1.5 s
Thus total time after which the sound of splash will be heard t=t1+t2
∴ t=10+1.5=11.5 s
Similar questions