Question

A stone is dropped from height 300m and at the same time another stone is projected vertically upwards with a velocity of 100

Answer 1

take h=100t-4.9t6^2-------------1

300=100t

t=3

h=255.9m

Answer 2

Answer:

3s and 255.9m

Explanation:

upward motion-

u = 100m/s g= -10

s=ut + 1/2 gt^2

s= 100t - 1/2 (10)t^2

s= 100t - 5t^2........1

downward motion

300- s = 100t + 5t^2.........2

adding (1) & (2)

300=200t

t=3/2s

from eqn. 1

s = 100*3/2-5*(3/2)^2

and answer will give u the height at which the stones will meet from the ground