A stone is dropped from height 90m what will is velocity when it reach to ground
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initial velocity u=0
v^2=u^2+2as
v^2=0+2g(90)=1800
v=√1800=30√2
v^2=u^2+2as
v^2=0+2g(90)=1800
v=√1800=30√2
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