Question

a stone is dropped from height of 10 m if acceleration is 10 m/s calculate time to reach ground

Answer 1

Answer:

u = 0m/s

g = 10m/s^2

h = 10m

1st we have to find final velocity ;

v^2 = u^2 + 2gh

v^2 = ( 0m/s )^2 + 2 * 10m/s^2 * 10m

v^2 = 100m^2/s^2

v = √ 100m^2/s^2

v = 10m/s

t = ?

t = v - u / g

t = 10m/s - 0m/s / 10m/s^2

t = 0s

hope it helps

Answer 2

Answer:It will take near about 1 sec to reach ground

Explanation: