Question

A stone is dropped from height of 125 m. If g = 10 ms2, what is the ratio of distances travelled by it during the first and last second of its motion?

Answer 1

Your answer is placed above

Answer 2

Answer:

1:9

Explanation:

S  

1

​

=  

2

1

​

×g×1=5m

t=  

g

2h

​

 

​

=  

10

2×125

​

 

​

=5s

S  

5

​

=  

2

g

​

(2(5)−1)

=9×5=45m

S  

1

​

:S  

5

​

=1:9