Question

A stone is dropped from height of 50m on earth. At the same time , another stone is thrown vertically upwards from the ground with a velocity up from the ground of 50m/s . At what height from the ground will the two stones meet (g= -10m/s^2)

Answer 1

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$Initially \: one \: stone \: is \: thrown \: up \: with \: a \: velocity \: of \: 50 {ms}^{ - 1}$

Time taken to reach stationary

v = 0, u = 50, a = 10,

v = u + at

Solving we get 5s

Meanwhile in 5 seconds

$the \: other \: rock \: initially \: moving \: down \: with \: u = 50 {ms}^{ - 1} \: has \: now \: attained \: a \: velocity \: v.$

$a = + 10 {ms}^{ - 2}$

$v = u + at = 50 + 5(10) = 100 {ms}^{ - 1}$

$hence \: one \: rock \: has \: a \: velocity \: of \: 0 \: and \:\\ the\: other \: has \: a \: velocity \: of \: 100 {ms}^{ - 1}$

$hence \: relative \: velocity \: is100 {ms}^{ - 1}$

hope this will help you...

- @3idiots29