Question

A? stone is dropped from rest and Falls freely under gravity .calculate the distance covered by it in the first 2 seconds

Answer 1

u = 0

a= g
s = ut + 1/2 at^2
s= 0 + 1/2 at^2
s=1/2 g t^2

s = 9.8 x 4 / 2

s= 19.6 m

Answer 2

Answer:

• Distance covered is 19.6 m.

Explanation:

Given

• Initial velocity (u) = 0 m/s
• Acceleration due to gravity (g) = 9.8 m/s²
• Time taken (t) = 2 sec

To find

• Distance covered (h)

Solution

From equation of motion:

• h = ut + ½ gt²

So:

• h = 0 × 2 + ½ × 9.8 × 2²
• 0 + 19.6
• 19.6

Hence, the distance covered is 19.6 m.