Question

A stone is dropped from rest and falls freely under gravity . calculate the distance
covered by it in the first two seconds(g=9.8ms -2 )

Answer 1

Step-by-step explanation:

We have,,

Initial speed of the stone, u = 0 m/s

Time taken, t = 2 s

Acc due to gravity, a = -g = -9.8 m/s²

Therefore the distance travelled by the stone in first 2s is given by,

$\sf{s=ut+\frac{1}{2}at^{2}}$

$\implies{\sf{s=(0)t-\frac{1}{2}gt^{2}}}$

$\implies{\sf{s=-\frac{1}{2}\times{9.8}\times{3}^{2}}}$

$\implies{\sf{s=-4.9\times{9}}}$

$\implies{\boxed{\sf{s=-44.1\:m}}}$

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