Question

A stone is dropped from rest at a height of 2.0 m above the surface of a planet. The planet has no atmosphere.
The speed of the stone just before reaching the surface of the planet is 3.8 m / s. What is the acceleration of free fall on the planet?

A) zero B) 1.9m/s^2 C) 3.6m/s^2 D) 7.2m/s^2

Answer 1

Answer:

The correct answer will be -

The acceleration due to free fall on that planet will be 3.61 m/s².

Explanation:

Given in the question -

• The stone is dropped from rest at a height of 2 m above the surface of the planet.
• There is no atmosphere so we can say that drag is zero.
• Speed of stone just before reaching the surface is 3.8 m/s.

We have to find the acceleration of free fall on the planet.

Initial velocity, u = 0

Final velocity, v = 3.8 m/s

Displacement, s = 2 m

acceleration, a =?

Using -

$v^2 = u^2 + 2as\\\\(3.8)^2 = 0 + 2\times a\times 2\\\\a = \frac{14.44}{2\times 2} = 3.61\ m/s^2$

So, the acceleration due to free fall on that planet will be 3.61 m/s².

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