Question

a stone is dropped from rest from the top of a building 44.1m high . IT takes 3s to reach the ground . use this information to calculate g.​

Answer 1

Explanation:

Initial velocity(u ) = 0

using formula for displacement in t th second

⇒ 44.1 = 1/2 x 9.8  (2t-1)

⇒(44.1 x 2)9.8 + 1 = 2t

⇒10/2 = t

⇒t = 5 sec

so using equation

⇒s = 0 + 1/2 x 9.8 x (5)²

⇒s = 4.9 x 25

⇒s = 122.5 m

so total height = 122.5

Answer 2

Answer:

acceleration due to gravity=9.8m/s^2

by using equation of motion,

s=ut+1/2at^2

s=0×3+1/2×a×(3)^2

44.1=1/2×a×(3)^2

a=44.1×2/9

a=9.8m/s^2

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