A stone is dropped from rising balloon at height of 76m above the ground and reaches the ground in 6sec. what was the velocity when the stone was dropped?
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Let the stone be released from the balloon at a height h above the geound, when the stone reaches the ground its displacement is -h. an upward velocity u = +10 m/s², and an acceleration due to gravity = -10 m/s², t = 11 second
-h = 10×11 -½ × 10× 11²= 110 - 5×121= 110 - 605 = - 495 m.
ie h= 495 m.
ie the height from where the stone is dropped = 495 m
I hope.. It is correct
-h = 10×11 -½ × 10× 11²= 110 - 5×121= 110 - 605 = - 495 m.
ie h= 495 m.
ie the height from where the stone is dropped = 495 m
I hope.. It is correct
Navpreet49:
thanks bro
for your help
ok
wlcm dear
Answered by
1
Answer:
Hope you find it easy to understand.
Explanation:
We have to take the displacement as negative i.e -76m
Then solve it by the equation of motion...
S=ut +1/2 at^2
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