Question

a stone is dropped from the 40m high tower . calculate its speed after 2 sec.also find the speed with which the stone strike the ground.

Answer 1

speed = distance/time = 40/2=20 m per second sq..

Answer 2

Hi User,

Given that,

Height = 40 m

Time t =2 sec

We know that,

v=u+gt

v=0+9.8×2

v=19.6m/s

The speed of stone is 19.6 m/s

Now, the speed with which the stone strikes the ground

=0+2×9.8×40

=784

v=28m/s

Hence, the speed with which the stone strikes the ground is 28 m/s