A stone is dropped from the building top takes 4 sec to reach the ground .find the height of the building ? (g=9.8m/s²)
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Explanation:
t=√2h/g,4=√2h/9.8, squaring on both sides 16=2h/9.8,h=9.8x16/2=9 .8x8=78.4 i hope it helps you please mark me as brainliest by A L V SAHASRA
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Explanation:
task-to find the height of thee the building
solution-A stone moved with initial zero velocity and constant acceleration=g=9.8m/s² due to gravitation.therefore the distance with it passes by time 't' is given by the formula
d(t)=gt²/2
for t = 4 this distance is equal to height 'h' of the building
h = a (4s) = 9.8 × 4²/2 = 9.8 × 16/2
=9.8 × 8 = 78.4m/s²
ans = 78.4m/s²
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