Question

a stone is dropped from the edge of a roof find the distance travelled by stone in 2s after reach

Answer 1

we should consider the law that is acceleration due to gravity that is h=it+1/2gt^2.
so now the height we don't no so keep it as it is
and the initial velocity will be 0 and time = 2s

h=0×2+1/2×9.8×(2)^2 (g= 9.8m/s^2)
h=0+1/2×9.8×4
h= o+1×9.8×2 ( because 1/2×4= 2)

h=9.8×2
h=19.6m ( so h represents distance )

Answer 2

Question:

A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.