Question

A stone is dropped from the edge of a roof. find the distance travelled by the stone is 2 second after the release. take g =9.8ms-2 ​

Answer 1

Answer:

t= 2 sec

u=??

g=9.8 ms-2

v=0ms-2

s=??

Explanation:

first we need to find initial velocity

therefore,

v = u + at

0 = u + 9.8×2

hence u= -19.6ms-2

now, S=ut+ 1/2 at^2

S=-19.6×2+1/2×9.8×2

S=39.2+9.8

hence Distance travelled = 46m

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