A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.
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In the given free fall,
u = 0 m/s
t = 2 sec
g = 10 m/s²
g = (v -u) /t
10 = (v - o) /2
10 = v/2
10 × 2 = v
v = 20 m/s
Answered by
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Question:
A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.
Answer:
20 m/sec
Explained Answer:
Given:
- Initial Velocity = 0m/s
- Acceleration due to Gravity = 10m/s²
- Time = 2s
Formula:
- v = u + at
Here,
- v = Final Velocity
- u = Initial Velocity
- a = Acceleration due to Gravity
- t = Time
So, According to Question:
Asking:
Speed
- v = u + at
- v = 0 + 10 × 2
- v = 20 m/sec
So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.
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