Physics, asked by supriyaverma80, 2 months ago

A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.
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Answers

Answered by MrAadil
2

In the given free fall,

u = 0 m/s

t = 2 sec

g = 10 m/s²

g = (v -u) /t

10 = (v - o) /2

10 = v/2

10 × 2 = v

v = 20 m/s

Answered by Anonymous
1

Question:

A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

  • Initial Velocity = 0m/s
  • Acceleration due to Gravity = 10m/s²
  • Time = 2s

Formula:

  • v = u + at

Here,

  • v = Final Velocity
  • u = Initial Velocity
  • a = Acceleration due to Gravity
  • t = Time

So, According to Question:

Asking:

Speed

  • v = u + at
  • v = 0 + 10 × 2
  • v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.

 \LARGE { \blue{ \bf{20m/sec Ans}}}

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