Question

A stone is dropped from the edge of roof . Find the speed of the stone at 2/s after the stone was dropped...​

Answer 1

Answer:

9.8 m/s^2 ( earth's acceleration due to gravity).

Answer 2

Given:-

• Initial Velocity = 0m/s

• Acceleration due to gravity = 10m/s²

• Time given = 2s.

To Find:-

• Speed of the stone after 2 second.

Formulae used:-

• v = u + at

Where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time.

Now,

→ v = u + at

→ v = 0 + 10 × 2

→ v = 20m/s

After, 2 second the speed of the stone will be 20m/s.

EXTRA INFORMATION.

• When any body is dropped then we take u = 0.

• The force of gravity at the center of te earth is Zero

• The force of gravity at the pole is maximum and in Equator it is minimum

• When the object is thrown vertically upward we take v = 0.