Question

A stone is dropped from the edge of the roof find the distance travelled by the stone in 2sec after its release

Answer 1

Explanation:

The U (initial velocity) . we need to find V(final velocity).

and time given is 2 sec.

here g = 9.8 .

so v=u+gt

V=0+9.8×2

V=19.6

To find the distance we can use

2gs=v²-u²

2×9.8×s=(19.6)²-(0)²

19.6×s=384.16

s=384.16÷19.6

s=19.6m

Answer 2

Question:

A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.