Question

A stone is dropped from the edge of the roof.Find the speed of stone at 2sec after the stone was dropped.​

Answer 1

v=u+at

v=0+2×9.8

v=19.6m/s^2

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Answer 2

Question:

A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.