Question

a stone is dropped from the edge of the roof. Find the speed of the stone at 2 sec after the stone was dropped

Answer 1

Height of falling matters most. After 2 sec it will gain the momentum of v=g*t. where g=9.81m/s2 so velocity will be v=2×9.81 = 19.62 m/s

Answer 2

Question:

A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.