A stone is dropped from the height 19.6m how long the stone takes to travel the first meter and the last meter?
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s = ut + 0.5at^2
19.6 = 0 + 0.5 x 9.81 x t^2
19.6 = 0.5 x 9.81t^2
39.2 = 9.81t^2
t^2 = 3.99
t = 1.99 s
mgh = 0.5 mv^2
2gh = v^2
2 x 9.81 x 19.6 = v^2
v^2 = 384.552
Aproximatly v = 19.6 m/s
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Answer:
the last metre is travel in 0.05 second
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