a stone is dropped from the height 19.6m . What distances it travels during the first 0.1s and the last 0.1s of its motion
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This should be the brainliest question man!!
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First of all find the initial velocity by using the formula
v²–u²=2as
Then apply the formula of distance travelled by the body per second...
Sn = u + g/2(2n+1)
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