A stone is dropped from the height h, its potential energy is 9 times the kinetic energy.
When the velocity of the stone becomes double the velocity at that instant, find the ratio of
the new kinetic energy to the new potential energy.
Answers
Answered by
0
Answer:
Telling you about the answer wait until the end
Answered by
0
Answer:
2:3
Explanation:
Let at a particular distance the height is x and the stone is dropped from the height h.
The potential energy is given as,
PE=9×KE
mg(h−x)=9×mgx
x=
10
h
The new kinetic energy is given as,
KE
n
=4mgx
KE
n
=4mg×
10
h
KE
n
=
5
2
mgh
The potential energy is given as,
PE
n
=
5
3
mgh
The required ratio is given as,
r=
3
2
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