A stone is dropped from the roof of a building. it passes a window 1.5m high in 0.1 sec. find the distance between the top of the window and the roof.
Answers
Answer:
A stone is dropped from the edge of the roof. it passes a window 2m high in ... 2m high in 0.1 sec. how far is the roof above the top of the window. 2 ... Now, We have to find The distance between roof and top of the window
Explanation:
Answer:
step -1 journey from the top of windows A to bottom of window B
using h =it+1/2gt² we get
2= 0.1+1/2×9.8×(0.1)²
2=0.1u+4.9×10-2
=19.5 m/s
the velocity of the ball at the top is the window is 19.5
step -2 journey from the roof 0 to the top of window A
using the velocity at the top of the window = velocity of the ball end of falling through height h between the roof nad top of the window .
using the equation v²-u²=2gg we get
(19.5)²-0 = 2×9.8×h
h=19.5²/19.6
=19.4
this the roof is 19.4 form the top of window
thnku