A stone is dropped from the roof of a tower of height h. The total distance covered by the stone in the last 2
seconds of its motion is equal to the distance covered by it in the first four seconds. Find the height of the
tower.
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Answer:
A ball is dropped from the roof of a tower height =h
Total distance covered it in the last seconds of its motion
Solution
The distance covered in first 3 second
s=
2
1
at
2
=
2
1
×10×3
2
=45
If the ball takes in second to fall to ground. The distance covered in nth second
s
n
=u+
2
g
(2n−1)
=0+
2
10
(2×n−1)
=10n−5
Therefore, 45=10n−5
10n=50
n=5
Thereforeh=
2
1
=
2
1
gt
2
=
2
1
×10×25
=125m
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