Question

a stone is dropped from the top of 40m high tower. calculate it's speed after 2s also find the speed with which the stone strikes the ground​

Answer 1

Answer:Given that,

Height = 40 m

Time t =2 sec

We know that,

 v=u+gt

v=0+9.8×2

v=19.6m/s

The speed of stone is 19.6 m/s

Now, the speed with which the stone strikes the ground

v  

2

=u  

2

+2gs

v  

2

=0+2×9.8×40

v  

2

=784

v=28m/s

Hence, the speed with which the stone strikes the ground is 28 m/s

Answer 2

Question:

A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.