a stone is dropped from the top of a 40 m high tower. calculate its speed after 2s, also find the speed with which the stone strikes the ground
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Answered by
99
v = u + at
v = 0 + (9.8)(2)
v = 19.6ms
s = ut + 1/2at^2
40j = (0)t + 1/2 (10)t^2
40/5=t^2
8^1/2 = t
at this time speed can be calculated
using v = u + at
v = 0 + 10(8^1/2)
v = 20(2^1/2) ms
v = 0 + (9.8)(2)
v = 19.6ms
s = ut + 1/2at^2
40j = (0)t + 1/2 (10)t^2
40/5=t^2
8^1/2 = t
at this time speed can be calculated
using v = u + at
v = 0 + 10(8^1/2)
v = 20(2^1/2) ms
sowmy635:
plz explain me again...
i dont understand hw u got acceleration
aceleration due to gravity is (g) which is 9.8 or 10 approx. this acc. is taken in a freefall motion as in ur question . the gravitational pull acting on us or on any object under the atmosphere of earth is g .
ooh okay
thnk u soo muck :)
freefall motion is taken when a body falls without any force or velocity aplied
pleasures all mine ;-)
s.. i understand
in which standard u r
10
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28
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