Question

A stone is dropped from the top of a 40 m high tower. Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground.​

Answer 1

Answer in attachment.

Answer 2

Answer:

Given that,

Height = 40 m

Time t =2 sec

We know that,

$v=u+gt</p><p>$

$v=0+9.8×2$

 

$v=19.6m/s$

The speed of stone is 19.6 m/s

Now, the speed with which the stone strikes the ground

$v2=u2+2gs$

$v2=0+2×9.8×40$

$v2=784$

$v=28m/s$

Hence, the speed with which the stone strikes the ground is 28 m/s