Question

a stone is dropped from the top of a 45 m high building how fast will it be moving when it reaches the graund and what will its velocity be

Answer 1

Given,

Height (h) = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) = 0 m/s

∴ v² = u²+2gh

= v² = 2*9.8*45

= v² = 882

= v = √882

= v = 29.69 m/s

When the ball will reach ground, it will have a speed of 29.69 m/s.

I hope this helps.