A stone is dropped from the top of a 80 m high tower. Calculate its speed after 2s. Also find the speed with which it strikes the ground.
Answers
Answered by
0
Answer:
using the equation
v = gt
where v = velocity
g = 9.8 ( gravitational velocity)
t = 2s ( time )
the speed after 2s is v = gt
And you need to tell us after how much time it strikes on earth , otherwise we can't answer you cause insufficient statements
hope this helps
Answered by
1
Answer:
HEY!! HERE IS YOUR REQUIRED ANSWER STEPWISE-:
Given that,
Height = 40 m
Time t =2 sec
We know that,
v=u+gt
v=0+9.8×2
v=19.6m/s
The speed of stone is 19.6 m/s
Now, the speed with which the stone strikes the ground
v² = u² + 2gs
v² = 0 + 2 × 9.8 × 40
v² 784
v = 28 m/s
Hence, the speed with which the stone strikes the ground is 28 m/s
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