Question

A stone is dropped from the top of a tower 125 m high into a pond of water with at the base of the tower when the splash hall at the top 1 g is equal to 10 m per second square

Answer 1

Here is your answer ⤵⤵⤵

S = 500 m = distance to travel - for the stone

g = 10 m/sec/sec,        initial velocity of stone  u = 0

equation of the dynamics of stone :

     s = u t + 1/2 g t^2

       500 = 0  + 1/2 * 10 * t^2

  t =  10 sec

Immediately after touching the water, in a fraction of second, there is a sound wave produced on the surface of water - splashing of water.

time for sound to reach the top = distance to travel / speed = 

                 500 meter / 340 m/sec  = 25/17 sec

total time = 10 sec + 25/17 sec

HOPE IT HELPS YOU ☺☺ !!!