Question

A stone is dropped from the top of a tower 490 m high into a pond of water at the base of the tower. The splash is heard after (given g = 9.8 m/s2 , speed of sound = 350 m/s)

Answer 1

Time taken by splash to hear at the top is 11.47 s

Explanation:

Given data:  

h=500 m  

g = 10 m/s^2

v= 340 m/s

h= ut+(1/2)gt^2

500=0+(1/2)10 x t^2

Initial velocity , u= 0

t^2 = 1000/10 = 100

OR t=10 s

Let t' be the time taken by sound to reach the base of tower ,

then

t'=h/v=500/340=1.47 s

Total time "T" =t+t' = 10+1.47 = 11.47 s

Therefore time taken by splash to hear at the top is 11.47 s

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Answer 2

Answer:11.4s

Explanation:

h=490m

g=9.8m/s^2

v=350m/s

formula is,

h=ut+1/2gt^2

490=0xt + 1/2x9.8 x t^2

490=0 + 4.9 x t^2

490= 4.9 x t^2

490/4.9= t^2

100= t^2

t=10s

t'=h/v

t'=490/350

t'=49/35

t'=1.4s

t+t'=final t

10+1.4=11.4

THEREFORE sound of splash will be heard after 11.4s

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