A stone is dropped from the top of a tower 500 m height into a point of water at the base of the toy when is the place hard at the top? Given equal 10 MS power to and speed of sound 340 MS - 1
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The height of the tower (h) = 500 m
Let t be the time taken by the stone to reach the water surface.
As you know,
for a free fall, h = ut + 0.5gt^2
Here, initial velocity is zero as the ball is just dropped.
So, 500 = 0.5× 10× t^2
Therefore, t = 10 seconds.
The speed of sound = 340 m/s So,
the time taken for the sound to travel 500m upwards = 500/340
= 1.47 seconds.
The total time taken to hear the splash sound after dropping the stone
= 10 + 1.47 = 11.47 seconds
i hope it will help you
regards
Let t be the time taken by the stone to reach the water surface.
As you know,
for a free fall, h = ut + 0.5gt^2
Here, initial velocity is zero as the ball is just dropped.
So, 500 = 0.5× 10× t^2
Therefore, t = 10 seconds.
The speed of sound = 340 m/s So,
the time taken for the sound to travel 500m upwards = 500/340
= 1.47 seconds.
The total time taken to hear the splash sound after dropping the stone
= 10 + 1.47 = 11.47 seconds
i hope it will help you
regards
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