Question

a stone is dropped from the top of a tower 500m high into a pond of water at the base of the tower . when is the splash heard ? g = 10m/s2 and speed of sound = 340m/s

Answer 1

first calculate time taken by stone to reach into the pond

hence

velocity just before impact , V = √[2gH]
= ✓[2×10×500]
= 100 m/s

t = √[2H/g]
= √(1000/10) = 10 sec for stone to arrive into the pond

t' = 500/340 = 1.47 sec for sound to arrive at the top

hence total time to get sound = t+ t'
T = 10+1.47 = 11.47 second

Answer 2

hey there !!

height = 500 m

time taken to reach ground (t1) = √2H/g

= √2×500/10

= 10 sec

speed of sound = 340 m/s

so time taken to reach at heigh of 500 m

time (t2) = distance/ speed = 500/340

= 1.470 sec


total time taken = t1 +t2 = 10 + 1.470

= 11.47 sec


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Hope it will help u