Question

A stone is dropped from the top of
a tower 500meter high into a pond of
water at the base of the tower when
is the splace hert at the top
given
g =10m/s2
speed = 3×14m/s

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Answer 1

CORRECT QUESTION :

• A stone is dropped from the top of the tower 500m high into the pond of water at the base of tower. When is the splash heard at the top of the tower. Given, g=10m/s2 and speed of sound is 340m/s.

A N S W E R :

• Distance (s) = 500 m
• Acceleration due to gravity (g) = 10 m/s²
• Speed of sound (v) = 340 m/s
• Initial velocity (u) = 0 m/s

★ By using second equation of motion we get :

• s = ut + ½ gt²

★ Plug in the given values in above equation of motion :

→ 500 = 0 × t + ½ × 10 × (t)²

→ 500 = ½ × 10 × t²

→ 500 = 5 × t²

→ t² = 500 ÷ 5

→ t² = 100

→ t = √100

→ t = 10 seconds

★ Now, let's calculate time taken by the sound to reach the top from the base of the :

→ t' = Distance ÷ speed of sound

→ t' = 500 ÷ 340

→ t' = 50 ÷ 34

→ t' = 1.47 seconds

★ The splash heard at the top of the tower :

→ Total time = t + t'

→ Total time = 10 + 1.47

→ Total time = 11.47 seconds