Question

a stone is dropped from the top of a tower 96 metre tall at the same instant and the stone is thrown vertically upwards from the foot of the tower with the velocity of 24 metre per second when and where will the two stones meet?​

Answer 1

Answer:

80 m from top after 4 sec

Explanation:

a stone is dropped from the top of a tower 96 metre tall at the same instant and the stone is thrown vertically upwards from the foot of the tower with the velocity of 24 metre per second when and where will the two stones meet?​

Let say after t sec both stones meets

Using S = ut + (1/2)at²

Distance Traveled by stone dropped

= 0*t + (1/2)gt²

= gt²/2

Distance Traveled by stone thrown upward

= 24*t  + (1/2)(-g)t²

= 24t - gt²/2

Distance of both = tower height = 96 m

gt²/2 + 24t - gt²/2 = 96

=> t = 4 sec

Distance from top of tower = g(4)²/2 = 8g = 80 m

Distance from foot = 96 - 80 = 16 m