Question

A stone is dropped from the top of a tower. At the same time another stone is thrown up from the ground at 19.6 m/s .They meet after 2 second. Find the hight of the tower.​

Answer 1

Given:

For stone 1,

u = 0 m/s

For stone 2,

u = 19.6 m/s

Let us suppose they meet at height 's' after 2 seconds

Answer:

The height (h) of the tower is 39.2 m

For detailed explanation, please refer to the attachments (4 attachments)

Note: I've taken acceleration under gravity equal to 10 m/s

PS- I'm sorry for any calculation mistakes, if there are any!