A stone is dropped from the top of a tower. If it travels 34.3 m in the last second
before it reaches the ground, find the height of the tower.
(g = 9.8 m/s2)
a) 39.2 m
b) 58.8 m
c) 78.4 m
d) 98 m
Answers
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1
Answer:
9.8m Or 98m
Explanation:
Given :
intial velocity (u) = 0
final velocity (v) = ?
g =9.8 m/s
time = 1second
height of the tower = v = u+ gt
v= 0+ 9.8 x 1
v = 9.8m/s
By the second equation of gravitation
S= 1/2 ut + gt2
S = 1/2 x 0 + 9.8 x (1)
S = 0 + 9.8
S= 9.8m
height =9.8m or 9.8x 10
= 98m
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