Question

a stone is dropped from the top of a tower of height 100m . the stone penetrates in the sand on ground through a distance of 2m . calculate retardation of stone

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Answer 1

Answer:

the stone is being dropped from the top of a tower of height 100 m.  

which means the potential energy is being converted to kinetic energy.

just before hitting the sand:

potential energy = kinetic energy  

mgh =  

u² =  

u² = 2gh

u² = 2 × 9.8 × 100  

u² = 1960

and we also know that:

v² = u² + 2as

as the retardation is negative the sign will get changed to:

v² = u² - 2as  

we will take the final velocity as 0 because the stone comes to rest after hitting the sand.

0 = 1960 - 2 × a × 2             ( given: the stone penetrates in the sand on the ground through a distance of 2m )

-4a = -1960

a= 490 m/ s

Explanation:

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